eureka math grade 5 lesson 14 homework 5.3 answer key

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5th grade (Eureka Math/EngageNY)

Unit 1: module 1: place value and decimal fractions, unit 2: module 2: multi-digit whole number and decimal fraction operations, unit 3: module 3: addition and subtractions of fractions, unit 4: module 4: multiplication and division of fractions and decimal fractions, unit 5: module 5: addition and multiplication with volume and area, unit 6: module 6: problem solving with the coordinate plane.

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Exit ticket solutions, exit ticket: eureka math grade 5 module 3 lesson 14.

Click the link for the answers to this lesson's exit ticket.

https://drive.google.com/open?id=0Bze4eU0rInwwUU5laTRsaFB6MUk

EngageNY (Eureka Math) Grade 5 Module 3 Answer Key

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Latitude and longitude of Moscow

Moscow (russia) latitude longitude.

• Moscow, Russia Latitude & Longitude
• GPS Coordinates of Moscow, Russia
• UTM Coordinates of Moscow, Russia
• Where is Moscow Russia?
• Cities of Moscow (Russia) GEO Codes

What is the latitude and longitude code of Moscow? The latitude of Moscow, Russia is 55.75582600, and the longitude is 37.61729990. Moscow is located at Russia country in the states place category with the gps coordinates of 55° 45' 20.974'' N and 37° 37' 2.28 E. Geographic coordinates are a way of specifying the location of a place on Earth, using a pair of numbers to represent a latitude and longitude. These coordinates are used to indicate the position of a point on the surface of the Earth, with the latitude representing the distance north or south of the equator and the longitude representing the distance east or west of the prime meridian. By using these coordinates, it is possible to pinpoint the exact location of a place on the globe.

🧭   GPS coordinate of Moscow, Russia

Here you will find the GPS coordinates and the longitude and latitude of Moscow . Coordinates of Moscow, Russia is given above in both decimal degrees and DMS (degrees, minutes and seconds) format. The country code given is in the ISO2 format. Are you a resident of Moscow, Russia? We're looking to verify and update our data. If you notice any inaccuracies or outdated information, please let us know .

🗺️   UTM coordinate of Moscow, Russia

Moscow, Russia, is precisely mapped in the UTM coordinate system, located in zone 37U. Its UTM Northing coordinate is 6180088.5226463, and the UTM Easting coordinate is 601497.55087408, providing a detailed and specific location within the global grid. Additionally, Moscow's location is encoded as ucfv0n014x7c in the GeoHash system, a compact representation that is useful for various geospatial applications. These coordinates offer an accurate and efficient way to pinpoint Moscow's exact position for mapping and navigation purposes.

📍 Where is Moscow, Russia on Map Lat Long Coordinates?

Where is Moscow, Russia, location on the map of Russia ? Moscow is located in Russia country, in Europe continent (or region). Exact geographical coordinates, latitude and longitude 55.75582600, 37.61729990. Mapped location of Moscow, Russia (N 55° 45' 20.974", E 37° 37' 2.28"). Moscow is located in the time zone GMTMSK.

Moscow has 92 cities. Currency in use in Moscow is Russian Ruble (RUB) and to make an international call to this city, you must first dial the country code +7. Current local time in Moscow, Russia .

● If you want to link to this Moscow latitude longitude page, please use the codes provided below!

Sending money to Russia? Send money to your friends, family or business partners in Moscow at a great rate with Wise. Over 14 million happy users. Low fees, fast transfers.

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Eureka Math Grade 5 Module 5 Lesson 13 Answer Key

Engage ny eureka math 5th grade module 5 lesson 13 answer key, eureka math grade 5 module 5 lesson 13 problem set answer key.

Question 1. Find the area of the following rectangles. Draw an area model if it helps you. a. \(\frac{5}{4}\) km × \(\frac{12}{5}\) km b. 16\(\frac{1}{2}\) m × 4\(\frac{1}{5}\) m c. 4\(\frac{1}{3}\) yd × 5\(\frac{2}{3}\) yd d. \(\frac{7}{8}\) mi × 4\(\frac{1}{3}\) mi Answer:

Therefore, 3 square kilometres

16 1/2 x 4 1/5

=  (16 x 4) + ( 16 x 1/5) + ( 4 x 1/2) x ( 1/2 x 1/5 )

= 64 + 16/5 + 2 + 1/10

Therefore, 69 3/10 square metres

4 1/3 x 5 2/3

4 x 5 + 4 x 2/3 + 5 x 1/3 + 1/3 x 2/3

= 20 +8/3 +5/3 +2/9

Therefore, 24 5/9 square yards

d.7/8 mi x 4 1/3 mi

= (7/8 x 4) + (7/8 x 1/3)

= 84/24 + 7/24

Therefore, 3 19/24 sq. mi

Question 2. Julie is cutting rectangles out of fabric to make a quilt. If the rectangles are 2\(\frac{3}{5}\) inches wide and 3\(\frac{2}{3}\) inches long, what is the area of four such rectangles? Answer:

Given, the measurements of the rectangles =

2 3/5 x 3 2/3

=( 2 x 3 ) + (2 x 2/3) + (3 x 3/5) + ( 3/5 x 2/3)

= 6 + 4/3 + 9/5 + 6/15

=6 + 3 8/15

= 9 8/15 square inches

Now, number of rectangles = 4

So, 4 x 9 8/15

= 36 + 2 2/15

Therefore, 38 2/15 square inches.

Given, the measurements of the lawn = 24 1/2 yd by 24 1/2 yd

The area of the lawn =

24 1/2 x 24 1/2

= (24 x 24 ) + (24 x 1/2 ) + (24 x 1/2) + ( 1/2 x 1/2)

= 576 + 12 +12 +1/4

=600 1/4 square yards

The area of the pool house = 16 square yards

The area of the pool =

7 1/2 yd x 2 1/2 yd

= 14 + 3 1/2 + 1 + 1/4

The area of sidewalk = 1 yd x 3 yd = 3 yd

Now, the amount of sod Howard needs to buy =

6001/4 – 16 – 18 3/4 – 3

= 581 1/4 – 18 2/4

= 580 5/4 – 18 3/4

= 562 1/2 square yards

Therefore, Howard need 562 1/2 square yards of sod.

Eureka Math Grade 5 Module 5 Lesson 13 Exit Ticket Answer Key

Find the area of the following rectangles. Draw an area model if it helps you. Question 1. \(\frac{7}{2}\) mm × \(\frac{14}{5}\) mm Answer:

7/2 mm x 4/5 mm

= 7/2 x 4/5

= 9 4/5 square mm

Question 2. 5\(\frac{7}{8}\) km × \(\frac{18}{4}\) km Answer:

5/8 km x 18/4 km

= 5/8 x 18/4

= 26 7/16 square kilometres.

Eureka Math Grade 5 Module 5 Lesson 13 Homework Answer Key

Question 1. Find the area of the following rectangles. Draw an area model if it helps you. a. \(\frac{8}{3}\) cm × \(\frac{24}{4}\) cm b. \(\frac{32}{5}\) ft × 3\(\frac{3}{8}\) ft c. 5\(\frac{4}{6}\) in × 4 \(\frac{3}{5}\) in d. \(\frac{5}{7}\) m × 6\(\frac{3}{5}\) m Answer:

8/3 cm x 24/4 cm

= 8/3 x 24/4

Therefore, 16 square centimetres

32/5 feet x 3 3/8

32/5 = 6 2/5

= 18 +  18/8 + 6/5 + 9/40

=  18 + 2 1/4 + 1 1/5 + 9/40

= 21 + 27/40

Therefore, 21 27/40 square feet

5 4/6 feet x 4 3/5 feet

( 5 x 4 ) + ( 5 x 3/5) + (4/6 x 4 ) + ( 4/6 x 3/5)

= 20 + 15/5 + 16/6 + 12/30

=20 + 3 + 8/3 + 2/5

= 25 +20/30 + 12/30

Therefore, 26 1/15 square inches

5/7 m x 6 3/5 m

= 5/7 x 6 3/5

=  30/7 + 15/35

= 4 2/7 + 3/7

Therefore, 4 5/7 square inches

Question 2. Chris is making a tabletop from some leftover tiles. He has 9 tiles that measure 3\(\frac{1}{8}\) inches long and 2\(\frac{3}{4}\) inches wide. What is the greatest area he can cover with these tiles? Answer:

Given, the measurements of the tiles =

3 1/8 x 2 3/4

= 6 + 9/4 + 2/8 + 3/32

= 6 +2 1/4 + 1/4 + 3/32

Now, the greatest area he can cover with 9 tiles=

= 9 x 8 19/32

= 72 + 191/32

= 72 +5 11/32

= 77 11/32 square inches.

Therefore, the greatest area he can cover = 77 11/32.

31 7/8 x 19 1/2

= ( 31 x 19) + ( 31 x 1/2 ) + (19 x 7/8 ) + ( 7/8 x 1/2)

= 589 + 31/2 + 133/8 + 7/16

= 589 + 15 1/2 + 16 5/8 + 7/16

= 620 + 1/2 + 5/8 + 7/16

= 630 + 8/16 + 10/16 + 7/16

= 620 25/16 square feet.

b. 13 3/5 feet x 11 3/4 feet

= ( 13 x 11) + ( 13 x 3/4 ) + (3/5 x 11 ) + ( 3/5 x 3/4)

= 143 + 9 3/4 + 6 3/5 + 9/20

=158 + 15/20 + 12/20 + 9/20

= 159 16/20

= 159 4/5 square feet

= 36 + 36/4

= 45 square feet

= 34 + 17/2

= 34 + 8 1/2

= 42 1/2 square feet

159 4/5 + 45 + 42 1/2

= 247 3/10 square feet

So, 621 9/16 – 247 3/10

= 384 21/80

Therefore, 384 21/80 square feet of carpeting is needed.

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